When applying 1/2 pound a.i. of weed killer 2E in 50 gallons of water per acre, how much is needed for 8 acres?

To determine the quantity of the weed killer solution needed for 8 acres, it is essential to first establish the total active ingredient (a.i.) being applied per acre and then scale that amount up for the entire area.

When applying 1/2 pound of active ingredient per acre, for 8 acres, you multiply the amount of a.i. per acre by the total number of acres:

1/2 pound per acre × 8 acres = 4 pounds of a.i.

Now, since the application involves using 50 gallons of water to deliver this active ingredient for each acre, you need to calculate the total volume of water for 8 acres:

50 gallons per acre × 8 acres = 400 gallons of water.

Next, you need to determine how much of the concentrated weed killer (2E) is required to achieve the desired application of 4 pounds of a.i.

With the concentration of the product being 2E, it typically means that there are 2 pounds of active ingredient per gallon of the product. So, to find out how many gallons are needed to meet the 4 pounds requirement, you divide the total pounds of a.i. needed by the concentration:

4 pounds ÷ 2 pounds per gallon